2013年7月25日星期四

Le meilleur matériel de formation examen EC-COUNCIL 312-49

Choisir le produit fait avec tous efforts des experts de Pass4Test vous permet à réussir 100% le test Certification IT. Le produit de Pass4Test est bien certifié par les spécialistes dans l'Industrie IT. La haute qualité du produit Pass4Test ne vous demande que 20 heures pour préparer, et vous allez réussir le test EC-COUNCIL 312-49 à la première fois. Vous ne refuserez jamais pour le choix de Pass4Test, parce qu'il symbole le succès.


Après une longue attente, les documentations de test EC-COUNCIL 312-49 qui combinent tous les efforts des experts de Pas4Test sont finalement sorties. Les documentations de Pass4Test sont bien répandues pendant les candidats. L'outil de formation est réputée par sa haute précision et grade couverture des questions, d'ailleurs, il est bien proche que test réel. Vous pouvez réussir le test EC-COUNCIL 312-49 à la première fois.


Le produit de Pass4Test que vous choisissez vous met le pied sur la première marche du pic de l'Industrie IT, et vous serez plus proche de votre rêve. Les matériaux offerts par Pass4Test peut non seulement vous aider à réussir le test EC-COUNCIL 312-49, mais encore vous aider à se renforcer les connaissances professionnelles. Le service de la mise à jour pendant un an est aussi gratuit pour vous.


Code d'Examen: 312-49

Nom d'Examen: EC-COUNCIL (Computer Hacking Forensic Investigator )

Questions et réponses: 150 Q&As

Vous pouvez télécharger le démo gratuit pour prendre un essai. Vous aurez plus confiance sur Pass4Test. N'hésitez plus à choisir la Q&A EC-COUNCIL 312-49 comme votre guide d'étude.


Nous croyons que pas mal de candidats voient les autres site web qui offrent les ressources de Q&A EC-COUNCIL 312-49. En fait, le Pass4Test est le seul site qui puisse offrir la Q&A recherchée par les experts réputés dans l'Industrie IT. Grâce à la Q&A de Pass4Test impressionée par la bonne qualité, vous pouvez réussir le test EC-COUNCIL 312-49 sans aucune doute.


312-49 Démo gratuit à télécharger: http://www.pass4test.fr/312-49.html


NO.1 What does the superblock in Linux define?
A. file system names
B. available space
C. location of the first inode
D. disk geometry
Answer: B, C, D

EC-COUNCIL   certification 312-49   312-49

NO.2 When examining a file with a Hex Editor, what space does the file header occupy?
A. the last several bytes of the file
B. the first several bytes of the file
C. none, file headers are contained in the FAT
D. one byte at the beginning of the file
Answer: D

EC-COUNCIL examen   312-49   312-49 examen   312-49

NO.3 It takes _____________ mismanaged case/s to ruin your professional reputation as a computer
forensics examiner?
A. by law, three
B. quite a few
C. only one
D. at least two
Answer: C

certification EC-COUNCIL   312-49   312-49   312-49 examen   certification 312-49   312-49

NO.4 A suspect is accused of violating the acceptable use of computing resources, as he has visited
adult websites and downloaded images. The investigator wants to demonstrate that the suspect
did indeed visit these sites. However, the suspect has cleared the search history and emptied the
cookie cache. Moreover, he has removed any images he might have downloaded. What can the
investigator do to prove the violation? Choose the most feasible option.
A. Image the disk and try to recover deleted files
B. Seek the help of co-workers who are eye-witnesses
C. Check the Windows registry for connection data (You may or may not recover)
D. Approach the websites for evidence
Answer: A

certification EC-COUNCIL   certification 312-49   312-49   certification 312-49

NO.5 In the context of file deletion process, which of the following statement holds true?
A. When files are deleted, the data is overwritten and the cluster marked as available
B. The longer a disk is in use, the less likely it is that deleted files will be overwritten
C. While booting, the machine may create temporary files that can delete evidence
D. Secure delete programs work by completely overwriting the file in one go
Answer: C

certification EC-COUNCIL   certification 312-49   312-49   312-49   312-49

NO.6 A(n) _____________________ is one that's performed by a computer program rather than the
attacker manually performing the steps in the attack sequence.
A. blackout attack
B. automated attack
C. distributed attack
D. central processing attack
Answer: B

certification EC-COUNCIL   312-49 examen   312-49 examen   312-49   312-49 examen   312-49

NO.7 With the standard Linux second extended file system (Ext2fs), a file is deleted when the inode
internal link count reaches ________.
A. 0
B. 10
C. 100
D. 1
Answer: A

EC-COUNCIL   certification 312-49   certification 312-49   certification 312-49

NO.8 In a computer forensics investigation, what describes the route that evidence takes from the time
you find it until the case is closed or goes to court?
A. rules of evidence
B. law of probability
C. chain of custody
D. policy of separation
Answer: C

EC-COUNCIL examen   certification 312-49   certification 312-49   312-49

NO.9 What file structure database would you expect to find on floppy disks?
A. NTFS
B. FAT32
C. FAT16
D. FAT12
Answer: D

EC-COUNCIL examen   312-49   certification 312-49   312-49

NO.10 A honey pot deployed with the IP 172.16.1.108 was compromised by an attacker . Given below is
an excerpt from a Snort binary capture of the attack. Decipher the activity carried out by the
attacker by studying the log. Please note that you are required to infer only what is explicit in the
excerpt. (Note: The student is being tested on concepts learnt during passive OS fingerprinting,
basic TCP/IP connection concepts and the ability to read packet signatures from a sniff dump.)
03/15-20:21:24.107053 211.185.125.124:3500 -> 172.16.1.108:111
TCP TTL:43 TOS:0x0 ID:29726 IpLen:20 DgmLen:52 DF
***A**** Seq: 0x9B6338C5 Ack: 0x5820ADD0 Win: 0x7D78 TcpLen: 32
TCP Options (3) => NOP NOP TS: 23678634 2878772
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.452051 211.185.125.124:789 -> 172.16.1.103:111
UDP TTL:43 TOS:0x0 ID:29733 IpLen:20 DgmLen:84
Len: 64
01 0A 8A 0A 00 00 00 00 00 00 00 02 00 01 86 A0 ................
00 00 00 02 00 00 00 03 00 00 00 00 00 00 00 00 ................
00 00 00 00 00 00 00 00 00 01 86 B8 00 00 00 01 ................
00 00 00 11 00 00 00 00 ........
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.730436 211.185.125.124:790 -> 172.16.1.103:32773
UDP TTL:43 TOS:0x0 ID:29781 IpLen:20 DgmLen:1104
Len: 1084
47 F7 9F 63 00 00 00 00 00 00 00 02 00 01 86 B8 G..c............
00 00 00 01 00 00 00 01 00 00 00 01 00 00 00 20 ...............
3A B1 5E E5 00 00 00 09 6C 6F 63 61 6C 68 6F 73 :.

没有评论:

发表评论